Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 9 - Counting and Probability - Exercise Set 9.4 - Page 564: 6

Answer

a. Yes b. No

Work Step by Step

a. Yes, since 7 integers > 5 possible remainders. There are 7 pigeons for 5 pigeonholes, so at least 2 will have the same remainder. Remainders when divided by 6 = {0, 1, 2, 3, 4, 5} 1 mod 6 = 1 2 mod 6 = 2 3 mod 6 = 3 4 mod 6 = 4 5 mod 6 = 5 6 mod 6 = 0 7 mod 6 = 1 8 mod 6 = 2 9 mod 6 = 3 b. No, since 7 integers < 8 possible remainders. There are less pigeons than pigeonholes. Remainders when divided by 8 = {0, 1, 2, 3, 4, 5, 6, 7}
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