Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 9 - Counting and Probability - Exercise Set 9.3 - Page 549: 5

Answer

a. 18000 integers are divisible by 5 b. 1/5 = 20% probability of random 5-digit integer being chosen that is divisible by 5.

Work Step by Step

A1 = integer ending with 0, A2 = integer ending with 5 a. N(A1) = 1*9*10*10*10 = 9000 N(A2) = 1*9*10*10*10 = 9000 N(A1 ⋃ A2) = 9000 + 9000 = 18000 integers are divisible by 5 b. 18000/((99999 – 10000) + 1)= 18/90 = 3*6/(3*30) = 1/5 = 20% probability of random 5-digit integer being chosen that is divisible by 5.
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