Answer
F:X->Y
Counter Example:
let {0,1} $\in$ X and {2} $\in$ Y
let F(0)=F(1) = 2
note that x1 ≠ x2 but f(x1)=f(x2)
which contradictes the definition of one-to-one ∀x1, x2 ∈ X, if F(x1) = F(x2) then x1 = x2.
Work Step by Step
F:X->Y
Counter Example:
let {0,1} $\in$ X and {2} $\in$ Y
let F(0)=F(1) = 2
note that x1 ≠ x2 but f(x1)=f(x2)
which contradicts the definition of one-to-one ∀x1, x2 ∈ X, if F(x1) = F(x2) then x1 = x2.