Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 4 - Elementary Number Theory and Methods of Proof - Exercise Set 4.8 - Page 226: 27

Answer

See below.

Work Step by Step

We will need to prove two statements: Proof1: "for all positive integers a and b, if a | b then lcm(a, b) = b." As a|b, let b=ka, we have lcm(a,b)=lcm(a, ka)=ka=b. Proof2: "for all positive integers a and b, if lcm(a, b) = b, then a | b." As lcm(a, b) = b, we have $b$ as multiplies of each component, in other words $b=ka$, thus $a|b$.
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