Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 4 - Elementary Number Theory and Methods of Proof - Exercise Set 4.6 - Page 206: 24

Answer

See below.

Work Step by Step

(a) To prove the statement by contraposition, we need to prove "for any real number $x$, if it is not an irrational, then its reciprocal $1/x$ will not be an irrational. To prove, let $x=\frac{a}{b}$ be a rational number where $a,b$ are non-zero integers, we have $\frac{1}{x}=\frac{b}{a}$ will also be a rational number (not an irrational). Thus we proved the statement by contraposition. (b) To prove the statement by contradiction, suppose there exist an irrational $y$ whose reciprocal is not an irrational, let the reciprocal be $\frac{1}{y}=\frac{c}{d}$ where $c,d$ are non-zero integers. We have $y=\frac{d}{c}$ will also be a rational which contradicts to the condition that $y$ should be an irrational. Thus, we proved the statement by contradiction.
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