Answer
$259\ div\ 11=floor(\frac{259}{11})$
$259\ mod\ 11=259-11\times floor(\frac{259}{11})$
Work Step by Step
Formula 4.5.1 at the bottom of page 195 tells us that $n\ div\ d=floor(\frac{n}{d})$ and $n\ mod\ d=n-d\times floor(\frac{n}{d})$. Note that the second equation follows directly from plugging the first equation into the quotient-remainder theorem.