Answer
$\exists n \in \mathbb{Z}$ such that n is prime and n is both even and n$\neq$ 2.
Work Step by Step
Recall the form of the negation of a universal conditional statement:
$~(\forall x, P(x) \rightarrow Q(x)) \equiv \exists x$ such that $(P(x) \land $ ~$Q(x))$
Recall also De Morgan's Laws for the negation of OR:
~$(p \lor q) \equiv$ ~p $\land$ ~q
