Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapters 1-10 - Cumulative Review Exercises - Page 759: 5

Answer

$1\frac{11}{12}$

Work Step by Step

We have $6\frac{2}{3} - 4\frac{3}{4}$ Solving $$\frac{20}{3} - \frac{19}{4}$$ $$\frac{80-57}{12} = \frac{23}{12} = 1\frac{11}{12}$$
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