## Basic College Mathematics (9th Edition)

$y=5$
Step 1. Subtract 2y from both sides of the equation. $5y-2y-5=2y-2y+10$ $3y-5=10$ Step 2. Add 5 to both sides. $3y-5+5=10+5$ $3y=15$ Step 3. Divide both sides by 3. $\frac{3y}{3}=\frac{15}{3}$ $y=5$