## Basic College Mathematics (9th Edition)

$z=6$
We are given the equation $-\frac{1}{2}z+2=-1$. In order to solve, we can first subtract 2 from both sides. $-\frac{1}{2}z+2-2=-1-2$ $-\frac{1}{2}z=-3$ Multiply both sides by -2. $(-\frac{1}{2}z\times-2)=z=-3\times-2=6$ $z=6$