Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 9 - Basic Algebra - 9.6 Solving Equations - 9.6 Exercises: 27

Answer

$d=\frac{7}{3}$

Work Step by Step

We are given the equation $d+\frac{2}{3}=3$. Subtract $\frac{2}{3}$ from both sides. $d+\frac{2}{3}-\frac{2}{3}=3-\frac{2}{3}$ $d+0=3-\frac{2}{3}=\frac{9}{3}-\frac{2}{3}=\frac{9-2}{3}=\frac{7}{3}$ $d+0=\frac{7}{3}$ Therefore, $d=\frac{7}{3}$.
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