Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.8 Pythagorean Theorem - 8.8 Exercises: 43

Answer

The diagonal brace of the rectangular gate is $\approx 5.7$ ft.

Work Step by Step

Let $H =$ hypotenuse of the triangle / diagonal brace of the gate $a^{2} + b^{2} = c^{2}$ $(4.5)^{2} + (3.5)^{2} = H^{2}$ $20.25 + 12.25 = H^{2}$ $32.5 = H^{2}$ $H = \sqrt 32.5$ $H = 5.701...$ $H \approx 5.7$ ft
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