Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.5 Triangles - 8.5 Exercises: 27

Answer

a) Frontage: 175 yd b) Area of the Lot: 8750 yd$^{2}$

Work Step by Step

a) The distance bordering the street is: 75 yd + 100 yd = 175 yd b) To find the total area of the shape we must break it into a triangle on the left and a rectangle on the right. Area of a Triangle: $A$$_{tri}$ = $\frac{1}{2}$$b$$h$ Area of a Rectangle: $A$$_{rec}$ = $l$$w$ $A$$_{tri}$ = $\frac{1}{2}$(75 yd)(100 yd) $A$$_{tri}$ = 3750 yd$^{2}$ $A$$_{rec}$ = (100 yd)(50 yd) $A$$_{rec}$ = 5000 yd$^{2}$ $A$$_{total}$ = $A$$_{tri}$ + $A$$_{rec}$ $A$$_{total}$ = 3750 yd$^{2}$ + 5000 yd$^{2}$ $A$$_{total}$ = 8750 yd$^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.