Basic College Mathematics (9th Edition)

a) Frontage: 175 yd b) Area of the Lot: 8750 yd$^{2}$
a) The distance bordering the street is: 75 yd + 100 yd = 175 yd b) To find the total area of the shape we must break it into a triangle on the left and a rectangle on the right. Area of a Triangle: $A$$_{tri} = \frac{1}{2}$$b$$h Area of a Rectangle: A$$_{rec}$ = $l$$w A$$_{tri}$ = $\frac{1}{2}$(75 yd)(100 yd) $A$$_{tri} = 3750 yd^{2} A$$_{rec}$ = (100 yd)(50 yd) $A$$_{rec} = 5000 yd^{2} A$$_{total}$ = $A$$_{tri} + A$$_{rec}$ $A$$_{total} = 3750 yd^{2} + 5000 yd^{2} A$$_{total}$ = 8750 yd$^{2}$