Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 2 - Multiplying and Dividing Fractions - Review Exercises - Page 191: 81

Answer

$\frac{49}{32}in^{2}$

Work Step by Step

Area = Length $\times$ width = $1\frac{3}{4}in \times \frac{7}{8}in$ = $\frac{7}{4} \times \frac{7}{8}in^{2}$ = $\frac{7\times7}{4\times8}in^{2}$ (multiply nominator and denominator) = $\frac{49}{32}in^{2}$
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