Elementary Geometry for College Students (5th Edition)

Published by Brooks Cole
ISBN 10: 1439047901
ISBN 13: 978-1-43904-790-3

Chapter 2 - Section 2.4 - The Angles of a Triangle - Exercises: 22

Answer

x=90$^{\circ}$ m$\angle$BAC=90$^{\circ}$ m$\angle$B=45$^{\circ}$

Work Step by Step

m$\angle$B+m$\angle$C+m$\angle$BAC=180 $\frac{x}{2}$+$\frac{x}{2}$+x=180 4x=360 x=90$^{\circ}$ m$\angle$BAC=x=90$^{\circ}$ m$\angle$B=$\frac{x}{2}$=45$^{\circ}$
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