Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises - Page 321: 50

$3\cdot(\int_{0}^{x} ({t^3+1})^{10}dt)^2 (x^3+1)^{10} $

Let's differentiate both sides and then use the chain rule to differentiate! $\frac{dy}{dx}=\frac{d}{dx}(\int_{0}^{x} ({t^3+1})^{10}dt)^3=3\cdot(\int_{0}^{x} ({t^3+1})^{10}dt)^2 (x^3+1)^{10} $