Answer
When $P=23,4lb/in^2$, V is approximately $628.2m^3$
Work Step by Step
$P_1 = 14.7lb/in^2$
$V_1 = 1000m^3$
$P_2 = 23.4lb/in^2$
$P_1=\frac{k}{V_1}$
$k=P_1V_1=14700$
$V_2=\frac{k}{P_2}$
$V_2\approx628.2$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 1: Functions - Section 1.1 - Functions and Their Graphs - Exercises 1.1 - Page 13: 62
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