Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 14 - Partial Derivatives - 14.1 Exercises - Page 914: 50

Answer

See image:

Work Step by Step

Level curves have the form: $k=\displaystyle \frac{y}{x^{2}+y^{2}}$ $x^{2}+y^{2}=\displaystyle \frac{y}{k}$ $x^{2}+(y^{2}-\displaystyle \frac{1}{k}y)=0$ $x^{2}+(y^{2}-\displaystyle \frac{1}{k}y+(\frac{1}{2k})^{2})-(\frac{1}{2k})^{2}=0$ $x^{2}+(y-\displaystyle \frac{1}{2k})^{2}=\frac{1}{4k^{2}}$ (circles around ($0, \displaystyle \frac{1}{2k}) $with radius $\displaystyle \frac{1}{2k}$ For graphing, $y=\displaystyle \pm\sqrt{\frac{1}{4k^{2}}-x^{2}}+\frac{1}{2k}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.