Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - 12.6 Exercises - Page 856: 4

Answer

Elliptic cylinder

Work Step by Step

There is no z in the equation, so the trace in the xy plane (where z=0) is the ellipse $4x^{2}+y^{2}=4$ Take the ellipse $4x^{2}+y^{2}=4$ in the xy plane and translate it into planes $z=k$, along the z-axis. What we obtain is an elliptic cylinder (see image).
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