Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 11 - Infinite Sequences and Series - Review - Exercises - Page 803: 4

Answer

Divergent

Work Step by Step

Given: $a_{n}=cos(n\pi/2)$ A sequence is said to be converged if and only if $\lim\limits_{n \to \infty}a_{n}$ is a finite constant. Now, $\lim\limits_{n \to \infty}a_{n}=\lim\limits_{n \to \infty}cos(n\pi/2)$ In this case, $a_{n}=[0,-1,0,1,0,-1,0,1,...]$ This implies that the sequence has no limit. Hence, the given sequence is divergent.
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