Answer
$3$
Work Step by Step
$1+\frac{1}{2}+\frac{1}{3}+...=\Sigma_{p=0}^\infty\Sigma_{q=0}^\infty\dfrac{1}{2^p3^q}$
$=\frac{1}{1-1/2}\frac{1}{1-1/3}$
$=3$
Multivariable Calculus, 7th Edition
by Stewart, James
Published by
Brooks Cole
ISBN 10:
0-53849-787-4
ISBN 13:
978-0-53849-787-9
Chapter 11 - Infinite Sequences and Series - Problems - Page 806: 6
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