Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 11 - Infinite Sequences and Series - 11.7 Exercises - Page 765: 27

Answer

Convergent

Work Step by Step

$\Sigma_{k=1}^{\infty}\frac{k lnk }{(k+1)^{3}}$ We note that $\sqrt k \gt lnk$ Then $\frac{\sqrt k}{k^{2}}=\frac{1}{k^{3/2}}$ As a series $\Sigma_{k=1}^{\infty}\frac{1}{k^{3/2}}$ converges because it is a p-series with $p=\frac{3}{2}\gt 1$
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