Answer
$-6+0i$
Work Step by Step
Use basic root properties $\sqrt{a}\sqrt{b}=\sqrt{ab}$ to simplify as follows:
$\sqrt{-3}\sqrt{-12}$
$\sqrt{3*-1}\sqrt{12*-1}$
$=\sqrt{3}i\sqrt{12}i$
$=\sqrt{3*12}i^{2}$
Since, $i^2=-1$ and $i=\sqrt{-1}$
$=\sqrt{36}\times(-1)$
$=-6$
or
$=-6+0i$
