Answer
$F=98.384(1.193)^{t}$ tons
where t = years after $2000$
Work Step by Step
Using desmos.com, we enter the table with the variables $t$ and $F$.
We enter in a free cell
$F\sim Ab^{t}$
place tick in "log mode" to obtain an exponential regression formula tying P to t, and the calculator returns (see image).
$A=98.384, b=1.193$
with the correlation coefficient $r$ being very close to $1$, indicating a good fit.
The model is
$F=98.384(1.193)^{t}$ tons
where t = years after $2000$.
