Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 8 - Section 8.3 - Measures of Central Tendency - Exercises - Page 576: 14

Answer

E(x) =$\frac{9}{2}$

Work Step by Step

E(x) =$2(\frac{1}{20})+4(\frac{15}{20})+6(\frac{2}{20})+8(\frac{2}{20})$ = $\frac{9}{2}$
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