Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 8 - Section 8.1 - Random Variables and Distributions - Exercises - Page 556: 33b

Answer

Shown below.

Work Step by Step

For the frequency, we count how many times each value occurs. We have: 2,000; frequency: 2 3,000; frequency: 1 4,000; frequency: 1 5,000; frequency: 1 6,000; frequency: 2 8,000; frequency: 3 To compute the probabilities, note from above that there are a total of 10 possibilities. So we have $P(X = 2,000)$ = 2/10 $P(X = 3,000)$ = 1/10 $P(X = 4,000)$ = 1/10 $P(X = 5,000)$ = 1/10 $P(X = 6,000)$ = 2/10 $P(X = 8,000)$ = 3/10
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.