Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 8 - Section 8.1 - Random Variables and Distributions - Exercises - Page 555: 21

Answer

$P(x<5) = \frac{2}{3}$

Work Step by Step

$X$ could be between 1 to 6, Therefore: $P(x<5) = P(1) + P(2) + P(3) + P(4) = \frac{1}{6} + \frac{1}{6} + \frac{1}{6} + \frac{1}{6} = \frac{4}{6} = \frac{2}{3}$
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