Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 7 - Section 7.7 - Markov Systems - Exercises - Page 532: 29

Answer

$v_∞=[\frac{2}{5}~~\frac{3}{5}]$

Work Step by Step

$v_∞=[x~~y]$ It must satisfy: $v_∞P=v_∞$ $[x~~y]\begin{bmatrix} .1 & .9 \\ .6 & .4 \\ \end{bmatrix} =[x~~y]$ It gives us two equations: $0.1x+0.6y=x$ $0.6y=0.9x$ $y=\frac{3}{2}x$ and $0.9x+0.4y=y$ $0.9x=0.6y$ $y=\frac{3}{2}x~~$ (But, it is the same equation) Also: $x+y=1$ $x+\frac{3}{2}x=1$ $\frac{5}{2}x=1$ $x=\frac{2}{5}$ $y=\frac{3}{2}x$ $y=\frac{3}{2}\times\frac{2}{5}=\frac{3}{5}$ Finally: $v_∞=[\frac{2}{5}~~\frac{3}{5}]$
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