Answer
$15$
$10$
Work Step by Step
We count how many ways he can choose 4 gummy bears out of 6. That is $C(6,4)=\frac{6!}{4!*2!}=\frac{6*5*4*3*2*1}{4*3*2*1*2*1}=3*5=15$
Next, we count how many ways he can choose three other gummy bears from the 5 gummy bears (other than the raspberry one). That is $C(5,3)=\frac{5*4*3*2*1}{3*2*1*2*1}=5*2=10$
We conclude that 10 outcomes include the raspberry gummy bear.
