Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 6 - Review - Review Exercises - Page 442: 39

Answer

$58,500$

Work Step by Step

There are 26 letters in the alphabet, and there are 10 different digits. The first letter in the code can be any letter of the alphabet =26 choices The second letter in the code can not be the same as the first letter, but can be any other: 25 choices. The first digit in the code can not be 0, but can be any other digit: 9 choices. The second digit can be any digit, that is 10 choices Therefore the number of different codes is $26*25*9*10=58,500$ 58,500 different customers can be identified.
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