Answer
$\$ 810.65$
Work Step by Step
The present value of an investment earning interest at$\\$
an annual rate of r$=4.2\%=0.042 \\$
compounded m$=52$ times per year $\\$
for a period of t$=5$ years,$\\$
with future value FV$=1000$ is$\\\\$
$ PV=\displaystyle \frac{FV}{(1+\frac{r}{m})^{mt}}=\frac{1000}{(1+\frac{0.042}{52})^{52(5)}}\approx$810.652955668$\\\\$
rounded to the nearest cent: $\$ 810.65$