Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.7 - The Coordinate Plane - Exercises - Page 38: 5

Answer

graph of given equation $x + y = 1$ is a straight line as following-

Work Step by Step

Given equation- $x + y = 1$ To sketch graph of this equation, first we will find three points on it as following- Substituting $x = -2$ in given equation- $-2 + y = 1$ OR $ y = 1+2 = 3$ Hence a point $P (-2, 3)$ lies on the line. Now Substituting $x = 0$ in given equation- $0 + y = 1$ OR $ y = 1$ Hence another point $Q (0, 1)$ also lies on the line. Now Substituting $x = 1$ in given equation- $1 + y = 1$ OR $ y = 1 - 1 = 0$ Hence another point $R (1, 0)$ also lies on the line. Now we will mark the points $P, Q $ and $R$ on the graph paper and join these points to get the graph of given equation $x + y = 1$
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