Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.1 Properties of Functions - 2.1 Exercises: 26

Answer

$(-\infty,6)\cup(-6,6)\cup(6,\infty)$

Work Step by Step

The domain is the set of all possible values of x for which the value f(x) exists (is defined). $f(x)$ is defined only for those x which do not produce 0 in the denominator. So, excluded from the domain of real numbers are those x for which $x^{2}-36=0$ $x^{2}=36$ $x=\pm 6$ In interval notation, the domain is $(-\infty,6)\cup(-6,6)\cup(6,\infty)$
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