Answer
$$\int_{1}^{4}\frac{e^{\sqrt{t}}}{\sqrt{t}}dt=2e^{2}-2e$$
Work Step by Step
$$let\ u =\sqrt{t},\,du=\frac{1}{2\sqrt{t}}dt$$
$$\int_{1}^{4}\frac{e^{\sqrt{t}}}{\sqrt{t}}dt=\int_{1}^{2}2e^{u}du$$
$$=\left [ 2e^{u} \right ]_{1}^{2}=2e^{2}-2e$$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 7 - Section 7.5 - Strategy for Integration - 7.5 Exercises - Page 507: 18
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