Answer
$\frac{2}{5\pi}$
Work Step by Step
$f_{avg}=\frac{1}{b-a}f(x)dx$
$=\frac{1}{\pi}\int_{0}^{\pi}cos^4(x)sin(x)dx$
$=\frac{1}{\pi}\left[-\frac{1}{5}cos^5(x)\right]_{0}^{\pi}$
$=\frac{2}{5\pi}$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 6 - Section 6.5 - Average Value of a Function - 6.5 Exercises - Page 463: 7
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