Answer
a) $3.54459$
b) $2.66521$
Work Step by Step
$y=x^2$
$y=\sqrt{1-x^2}$
a) Intersection points:
$\sqrt{1-x^2}=x^2; 1-x^2=x^4$
$x_1=-0.786151;x_2=0.786151$
$\pi\int_{-0.786151}^{0.786151}((1-x^2)-x^4)dx=3.54459$
b)Intersection points:
$\sqrt{1-x^2}=x^2; 1-x^2=x^4$
$y_1=0;y_2=0.618034$
$y_3=0.618034;y_4=1$
$\pi\Big(\int_{0}^{0.618034}(1-y^2)dy+\int_{0.618034}^{1}(y)dy\Big)=2.66521$