Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Section 5.1 - Areas and Distances - 5.1 Exercises - Page 376: 16

Answer

54694 ft

Work Step by Step

The question wants the distance traveled by the Endeavor after ONLY 62 seconds. As $$distance = velocity * time$$ and since the time intervals are not the same, you should multiply the time intervals by the upper limit of the function value: $$(10-0)*185 + (15-10)*319+(20-15)*447+(32-20)*742+ (59-32)*1325+ (62-59)*1445 \approx 54694 ft$$
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