## Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning

# Chapter 5 - Review - True-False Quiz: 8

False

#### Work Step by Step

Consider $f(x)=6,g(x)=x, a=-4, b=4$ Therefore, $f(x)\geq g(x)$ on $(-4,4)$ However $f'(x) \leq g'(x)$, since $f'(x)=0$ and $g'(x)=1$ Hence, the statement is false.

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