Answer
$$g'(x)=2\sinh x\cosh x$$
Work Step by Step
$g'(x)=\frac{d}{dx}\sinh^2 x$
Using the chain rule:
$g'(x)=\frac{d\sinh^2 x}{d \sinh x}
\times \frac{d\sinh x}{dx}$
$=2\sinh x
\times \cosh x$
$=2\sinh x\cosh x$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 3 - Section 3.11 - Hyperbolic Functions - 3.11 Exercises - Page 264: 32
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