## Calculus: Early Transcendentals 8th Edition

a) $\lim\limits_{x \to 2-}$ f(x) = 3 b) $\lim\limits_{x \to 2+}$ f(x) = 1 c) $\lim\limits_{x \to 2}$ f(x) doesn't exist. d) f(2) = 3 e) $\lim\limits_{x \to 4}$ = 4 f) f(4) doesn't exist.
a) As x approaches 2 from the left, the value of $\lim\limits_{x \to 2-}$ = 3 b) As x approaches 2 from the right, the value of $\lim\limits_{x \to 2+}$ = 2 c) Because the value of $\lim\limits_{x \to 2-}$ $\ne$ the value of $\lim\limits_{x \to 2+}$, the $\lim\limits_{x \to 2}$ doesn't exist. d) At x = 2, f(2) = 2 ( The dark point) e) When x approaches 4, the left and right limits are the same ( = 4), so the $\lim\limits_{x \to 4}$ = 4 f) When x = 4, f(4) is undefined ( the circle, white point).