Answer
This is not true.
Work Step by Step
This is not true.
The function $$f(x)=\left\{_{1,\quad x\geq 0}^{-1,\quad x<0}\right.$$ is not continuous at $x=0$, but the function $|f(x)|=1$ is continuous.
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 2 - Review - True-False Quiz - Page 166: 26
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
