Answer
$\lt y^2cos(xy) ,sin(xy)+xycos(xy)\gt$
Work Step by Step
$f(x,y)=ysin(xy)$
$f_x(x,y)=y^2cos(xy)$
$f_y(x,y)=sin(xy)+xycos(xy)$
Gradient vector field of $f$ is: $\lt y^2cos(xy) ,sin(xy)+xycos(xy)\gt$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 16 - Section 16.1 - Vector Fields - 16.1 Exercise - Page 1074: 21
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