## Calculus: Early Transcendentals 8th Edition

$(0, 2) \cup (2,\infty)$
First, we must find where our limiting components are defined: $ln \ t$ is defined when $t>0$ The denominator $t-2$ is defined when $t\ne2$ Looking at these components, we can see our domain is limited to $(0, 2) \cup (2,\infty)$.