Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Review - Exercises - Page 690: 18

Answer

$r= \sqrt 2$

Work Step by Step

$x^2+y^2=2$ To convert this equation into a polar equation, put $x=rcos\theta$ and $y=rsin \theta$ $r^2cos^2\theta + r^2sin ^2\theta =2$ $ r^2=2$ $r= \sqrt 2$
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