## Calculus: Early Transcendentals 8th Edition

a) $(-5, 3)$ b) $(-5, -3)$
a) Since the function is even, $f(x) = f(-x)$ $f(5) = f(-5)=3$ $\therefore (-5, 3)$ must also be on the graph. b) Since the function is odd, $f(x) = -f(-x)$ $f(5) = -f(-5)=3$ $f(-5)=-3$ $\therefore (-5, -3)$ must also be on the graph.