Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 6 - Applications of Integration - Review Exercises - Page 509: 52

Answer

$14\ \text{units}$

Work Step by Step

The mass can be calculated as: $Mass, M=\int_0^6 \rho(x) \ dx=\int_0^2 1 \ dx+\int_2^4 2 \ dx+\int_4^6 4 \ dx$ or, $=[x]_0^2+[2x]_2^4+[4x]_4^6$ or, $=2+2(4-2)+4(6-4)$ or, $=14\ \text{units}$
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