## Calculus: Early Transcendentals (2nd Edition)

Published by Pearson

# Chapter 4 - Applications of the Derivative - Review Exercises: 76

#### Answer

$${e^{2x}} + C$$

#### Work Step by Step

\eqalign{ & \int {2{e^{2x}}} dx \cr & {\text{take out the constant}} \cr & = 2\int {{e^{2x}}} dx \cr & {\text{use the formula }}\int {{e^{ax}}dx} = \frac{1}{a}{e^{ax}} + C \cr & = 2\left( {\frac{1}{2}{e^{2x}}} \right) + C \cr & {\text{simplify}} \cr & = {e^{2x}} + C \cr}

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