#### Answer

$${e^{2x}} + C$$

#### Work Step by Step

$$\eqalign{
& \int {2{e^{2x}}} dx \cr
& {\text{take out the constant}} \cr
& = 2\int {{e^{2x}}} dx \cr
& {\text{use the formula }}\int {{e^{ax}}dx} = \frac{1}{a}{e^{ax}} + C \cr
& = 2\left( {\frac{1}{2}{e^{2x}}} \right) + C \cr
& {\text{simplify}} \cr
& = {e^{2x}} + C \cr} $$