Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 4 - Applications of the Derivative - 4.1 Maxima and Minima - 4.1 Exercises - Page 243: 52

Answer

(a) $x = 2.5$ is the only critical number. (b) The maximum revenue is $\$375$, which occurs when the price is $\$2.50$.

Work Step by Step

(a). $R'(x) = −120x + 300$, which is zero when $x = 2.5$. This is the only critical number. b. The maximum must occur at either an endpoint or a critical point. Note that $R(0) = 0$, $R(2.5) = 375$, and $R(5) = 0$, so the maximum revenue is $\$375$, which occurs when the price is $\$2.50$.
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