Answer
-1.5
Work Step by Step
$\frac{d}{dx}(\frac{f(x)}{g(x)})$ evaluated @ x=2
$=\frac{g(x)f'(x)-f(x)g'(x)}{g(x)^{2}}$
$=\frac{g(2)f'(2)-f(2)g'(2)}{g(2)^{2}}$
$=\frac{2\times5-4\times4}{2^{2}}$
$=\frac{-6}{4}$
$=-1.5$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 3 - Derivatives - 3.4 The Product and Quotient Rules - 3.4 Exercises - Page 161: 75
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