Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.2 Definitions of Limits - 2.2 Exercises - Page 68: 40

Answer

$2$

Work Step by Step

We are given the function: $f(x)=\dfrac{18(\sqrt[3]x-1)}{x^3-1}$. In order to determine $\lim\limits_{x \to 1} f(x)$, we graph $f(x)$ and use zoom and trace features to approximate the limit. We got: $\lim\limits_{x \to 1} \dfrac{18(\sqrt[3]x-1)}{x^3-1}=2$
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